HOW DO WAVES INTERACT WITH MATTER?
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ELECTROMAGNETIC ENERGY IS CARRIED BY PHOTONS:
SINGLE QUANTA OF LIGHT.
The energy of one photon of a particular frequency is:
E = h nu = h c / lambda
h = 6.63 x 10^{-34} J.s = 6.63 x 10^{-27} erg.s
is PLANCK's CONSTANT.
(Along with c, the speed of light; e, the charge on
an
electron (or proton) and G (Newton's constant
of gravity),
h is one of the
FUNDAMENTAL CONSTANTS of NATURE.)
These PHOTONS can equally well explain
BUT they can't explain
On the other hand the WAVE picture can't explain:
WE WILL DISCUSS THESE TOPICS IN DETAIL LATER;
FOR NOW, LET'S TURN TO:
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RADIATION, TEMPERATURE & POWER
Crudely, hotter matter produces more highly
accelerated charged
particles, which therefore produces
more powerful EM radiation.
Heat energy is proportional to temperature:
E = k T
(where T is in Kelvins, 0 at ABSOLUTE ZERO).
So the thermal (heat) energy in atoms should be
proportional to the photon energy: using math
(We use "propto" to mean "proportional to")
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TEMPERATURE SCALES
Pretty much only the US has stuck with Farenheit temperatures;
the rest of the world normally uses Celcius, but
BECAUSE ENERGIES VANISH AT ABSOLUTE ZERO, THE NATURAL
TEMPERATURE SCALE IS KELVIN and we'll usually use it.
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WIEN's LAW
lambda_{max} = 0.29 cm.K / T (K)
THIS IS THE PEAK WAVELENGTH FOR BLACKBODY
(or THERMAL or
PLANCKIAN)
EMISSION FROM A
SOLID, LIQUID or DENSE GAS.
Example: T = 5800 K = 5.8 x 10^3 K
WE DID SEVERAL OTHER EXAMPLES USING TODAY'S FORMULAS IN CLASS.
SIMILAR EXAMPLES AND PROBLEMS ARE IN THE TEXTBOOK AND ON ITS WEBSITE.